Language of Physics

Introduction

Physics often describes the universe and its phenomena using the language of mathematics, where the Cartesian 3D space serves as the natural stage for physical events. This spatial representation, defined by three orthogonal axes \(x\), \(y\), and \(z\), is the starting point for our exploration. By reducing the dimensionality to 2D, we simplify the analysis, enabling a focused study of structures that arise in such spaces. This reduction is not merely an abstraction but also a practical tool for understanding the behaviors and interactions within physical systems.

Weather Data Visualization

Interactive weather maps serve as an excellent introduction to the fundamental ideas required to study physics. If one can interpret these maps, they will find it easier to grasp the basic concepts of scalar and vector fields, which are central to understanding physical systems.

On such maps, temperature is represented using a color gradient, where each color corresponds to a specific value at a given point in space. This visualization aligns with the definition of a scalar field, which assigns a single numerical value to each point in space.

Similarly, wind patterns are illustrated using moving line segments, where their length and direction represent the speed and direction of the wind at various points. These segments directly depict vector fields, as they assign a vector—defined by both magnitude and direction—to each point in space. Since the magnitude is expressed as a numerical value, the background color can be used to represent the magnitude of the vector field.

www.windy.com

Having this background, we can now delve into the mathematical representations of scalar and vector fields in 2D space. Let us use more formal definitions to understand these concepts better.

Scalar Fields

A scalar field associates a single real value to every point in a given space. In 2D, this can be represented as a function \(T(x, y)\), where \(T\) could represent a physical property like temperature.

Example: Temperature on a surface

Consider a simple model where the temperature of a surface varies with both position and time:

\[ T(x, y) = 5 \sin(x) \cos(y) \]

Below is a Python code of this scalar field:

import numpy as np
import matplotlib.pyplot as plt

# Scalar field definition
def scalar_field(x, y):
    return  5 * np.sin(x) * np.cos(y)

# Generate grid points
x = np.linspace(-5, 5, 100)
y = np.linspace(-5, 5, 100)
x, y = np.meshgrid(x, y)

# Compute scalar field values
T = scalar_field(x, y)

# Plot the scalar field
plt.figure(figsize=(8, 6))
plt.imshow(T, extent=[-5, 5, -5, 5], origin='lower', cmap="coolwarm")
plt.colorbar(label="Temperature")
plt.xlabel("X-axis")
plt.ylabel("Y-axis")
plt.title("Temperature Distribution on a Surface")
plt.show()

Above example defines a scalar field that do not depend on time. As we can see on weather maps, scalar fields can also be time-dependent, where the value of the field changes with time.

To define a time-dependent scalar field, we can modify the previous example by adding explicit time dependence:

\[ T(x, y, t) = 5 \sin(x) \cos(y) e^{-t} \]

Now the temperature at each point \((x, y)\) decays exponentially with time. To visualize this field, we can use the following Python

import numpy as np
import matplotlib.pyplot as plt

# Scalar field definition
def scalar_field(x, y, t):
    return 5 * np.sin(x) * np.cos(y) * np.exp(-t)

# Generate grid points
x = np.linspace(-5, 5, 100)
y = np.linspace(-5, 5, 100)
x, y = np.meshgrid(x, y)

# Compute scalar field values for 4 time steps
T = np.zeros((100, 100, 4))
for i in range(4):
    T[:, :, i] = scalar_field(x, y, i)

# Determine common color scale
vmin = np.min(T)
vmax = np.max(T)

# Plot the scalar field for 4 time steps
fig, axs = plt.subplots(2, 2, figsize=(12, 12))

# Store the last image for the colorbar
im = None

for i, ax in enumerate(axs.flat):
    ax.grid(False)  # Explicitly disable gridlines
    im = ax.imshow(T[:, :, i], extent=[-5, 5, -5, 5], origin='lower', cmap="coolwarm", vmin=vmin, vmax=vmax)
    ax.set_title(f"Temperature Distribution at t={i}")
    ax.set_xlabel("X-axis")
    ax.set_ylabel("Y-axis")

# Adjust layout to fit a colorbar outside the plots
fig.subplots_adjust(right=0.85)
cbar_ax = fig.add_axes([0.88, 0.15, 0.02, 0.7])  # Define a new axis for the colorbar
cbar = fig.colorbar(im, cax=cbar_ax)
cbar.set_label("Temperature")

plt.show()

or we can simulate this in an html animation:

html_anim/language_of_physics/scalar_field.html

Vector Fields

A vector field assigns a vector to every point in space. In 2D, such a field can be represented as

\[\vec{F}(x, y) = (F_x(x, y), F_y(x, y))\]

where \(F_x\) and \(F_y\) are the components of the vector field. Both may depend on the position \((x, y)\).

Example: Static vector field

Let us examine a vector field that depends on both space and time:

\[ \vec{F}(x, y) = (\sin(y), \sqrt{\frac{|x|}{5}}) \]

This field might represent the velocity of a fluid at each point \((x, y)\) in a 2D space. Below is a Python code to visualize this vector field:

import numpy as np
import matplotlib.pyplot as plt

# Definition of the vector field
def vector_field(x, y):
    Fx = np.sin(y)
    Fy = np.sqrt(np.abs(x)/5)
    return Fx, Fy

# Generating a grid of points
x = np.linspace(-15, 15, 16)
y = np.linspace(-15, 15, 16)
x, y = np.meshgrid(x, y)

# Calculating the vector field
Fx, Fy = vector_field(x, y)

# Calculating the lengths of the vectors
d_lengths = np.sqrt(Fx**2 + Fy**2)

# Initializing the plot
fig, ax = plt.subplots(figsize=(6, 6))
quiver = ax.quiver(
    x, y, Fx, Fy, d_lengths, angles='xy', scale_units='xy', scale=1, cmap='viridis'
)
cb = fig.colorbar(quiver, ax=ax, label="Vector length")
ax.set_xlim(-15, 15)
ax.set_ylim(-15, 15)
ax.set_xlabel("X axis")
ax.set_ylabel("Y axis")
ax.set_title("2D vector field with color dependent on vector length")

plt.show()

Stream plot

import numpy as np
import matplotlib.pyplot as plt

# Definition of the vector field
def vector_field(x, y):
    Fx = np.sin(y)
    Fy = np.sqrt(np.abs(x)/5)
    return Fx, Fy

# Generating a grid of points
x = np.linspace(-15, 15, 100)  # Higher resolution for streamlines
y = np.linspace(-15, 15, 100)
x, y = np.meshgrid(x, y)

# Calculating the vector field
Fx, Fy = vector_field(x, y)
d_lengths = np.sqrt(Fx**2 + Fy**2)

# Streamplot (Streamlines)
fig, ax = plt.subplots(figsize=(6, 6))
stream = ax.streamplot(
    x[0, :], y[:, 0], Fx, Fy, color=d_lengths, cmap='viridis', linewidth=1.5
)
cb = fig.colorbar(stream.lines, ax=ax, label="Vector length")
ax.set_xlim(-15, 15)
ax.set_ylim(-15, 15)
ax.set_xlabel("X axis")
ax.set_ylabel("Y axis")
ax.set_title("2D Vector Field with Streamlines")
plt.show()

Examples in html

Flow Speed (V_max): 5.0

Click and drag to place particles. Pause to arrange them, then Resume.

Derivatives and Integrals

Derivatives

Derivative of functions of one variable

The derivative of a function \(f(x)\) with respect to \(x\) is defined as

\[ \frac{df(x)}{dx} = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h} \]

This limit represents the rate of change of the function \(f(x)\) with respect to \(x\).

Derivative of functions of two variables

The derivative of a function \(f(x, y)\) with respect to \(x\) is defined as

\[ \frac{\partial f(x, y)}{\partial x} = \lim_{h \to 0} \frac{f(x + h, y) - f(x, y)}{h} \]

This limit represents the rate of change of the function \(f(x, y)\) with respect to \(x\). The derivative is a measure of how the function changes as \(x\) changes for a fixed value of \(y\). This describes how the function changes in the \(x\) direction.

Similarly, the derivative of a function \(f(x, y)\) with respect to \(y\) is defined as

\[ \frac{\partial f(x, y)}{\partial y} = \lim_{h \to 0} \frac{f(x, y + h) - f(x, y)}{h} \]

This limit represents the rate of change of the function \(f(x, y)\) with respect to \(y\) and describes how the function changes in the \(y\) direction for a fixed value of \(x\).

Html example

Point position (x): 1.00

Step size (h): 1.00

Δy / Δx ≈

Exact derivative f'(x):

Function: f(x) = 0.5x³ - x
Move 'h' close to 0 to see the approximation converge to the exact value.

X position: 1.00

Y position: 1.00

Function: f(x,y) = sin(x) * cos(y)
Red: Slice y=const (∂f/∂x). Blue: Slice x=const (∂f/∂y).

Integrals

Area under a curve

At the simplest level, an integral is the reverse of a derivative. The integral of a function \(f(x)\) with respect to \(x\) is defined as

\[ \int f(x) dx = F(x) + C \]

where \(F(x)\) is the antiderivative of \(f(x)\) and \(C\) is an integration constant. The antiderivative is a function whose derivative is equal to \(f(x)\):

\[ \frac{dF(x)}{dx} = f(x) \]

The integral is a measure of the area under the curve of the function \(f(x)\). The integral is a function that gives the area under the curve of the function \(f(x)\) up to a given point.

Line integrals

The line integral is a generalization of the integral to functions of multiple variables. The line integral of a vector field \(\mathbf{F}(x, y)\) along a curve \(C\) parameterized by \(\mathbf{r}(t) = (x(t), y(t))\) for \(t\) in \([a, b]\) is defined as

\[ \int_C \mathbf{F} \cdot d\mathbf{r} = \int_a^b \mathbf{F}(\mathbf{r}(t)) \cdot \mathbf{r}'(t) dt \]

where \(\mathbf{F} \cdot d\mathbf{r}\) is the dot product of the vector field \(\mathbf{F}\) and the differential element of the curve \(d\mathbf{r}\). The line integral is a measure of the work done by the vector field \(\mathbf{F}\) along the curve \(C\).

Numerically, the line integral can be approximated by dividing the curve into \(N\) small segments and summing the contributions from each segment:

\[ \int_C \mathbf{F} \cdot d\mathbf{r} \approx \sum_{i=1}^{N} \mathbf{F}(\mathbf{r}(t_i)) \cdot \Delta \mathbf{r}_i \]

where \(\Delta \mathbf{r}_i\) is the vector representing the \(i\)-th segment of the curve.

Html example

Rectangles (N): 5

Area ≈ 0.00 ( f(x) = 1 + 0.1x² + 0.5sin(2x) )

Segments (N): 10

Work ≈ 0.00

Draw with mouse/touch
Red: Force | Green: Displacement

Differential equations

Starting example

Let’s consider the first order differential equation

\[ \frac{dy(x)}{dx} = 2x \]

Let us think how we should read this equation. The left hand side is the derivative of the function \(y(x)\) with respect to \(x\). This derivative is equal to \(2x\). This equation tells us how the function \(y(x)\) changes with \(x\). The function \(y(x)\) changes at a rate of \(2x\) with respect to \(x\). This is a simple differential equation that can be solved by integration. \[ y(x) = x^2 + C \]

where \(C\) is an integration constant. This is the general solution of the differential equation. The solution is not unique because the constant \(C\) can take any value.

import numpy as np
import matplotlib.pyplot as plt

def y(x, C):
    return x**2 + C

x = np.linspace(0, 10, 100)

fig, ax = plt.subplots(figsize=(6, 4))

for C in range(-50, 50, 10):
    plt.plot(x, y(x, C), label=f'C={C}')

plt.xlabel('x')
plt.ylabel('y')
plt.show()

Numerical solution

Remember that derivatives can be approximated by finite differences. The derivative of a function \(f(x)\) can be approximated by

\[ \frac{df(x)}{dx} \approx \frac{f(x + h) - f(x)}{h} \]

where \(h\) is a small number. This is a simple way to approximate the derivative of a function. Let’s use this approximation to solve the differential equation

\[ \frac{dy(x)}{dx} = 2x \]

We can approximate the derivative by

\[ \frac{y(x + h) - y(x)}{h} = 2x \]

This equation can be solved for \(y(x + h)\)

\[ y(x + h) = y(x) + 2xh \]

This equation can be used to solve the differential equation numerically. We can start from an initial value of \(y(x)\) and use the equation above to calculate the value of \(y(x + h)\). This value can be used to calculate the next value of \(y(x + 2h)\) and so on:

• Step 1 - we know value of \(y\) for a given \(x\) which is

\[y(x)\]

• Step 2 - we can calculate the value of \(y\) for the next point \(x + h\) using

\[y(x + h) = y(x) + 2xh\]

• Step 3 - we can calculate the value of \(y\) for the next point \(x + 2h\) using

\[y(x + 2h) = y(x + h) + 2(x + h)h\]

• Step 4 - we can calculate the value of \(y\) for the next point \(x + 3h\) using

\[y(x + 3h) = y(x + 2h) + 2(x + 2h)h\]

• and so on

Let us compare the numerical solution with the analytical solution.

import numpy as np
import matplotlib.pyplot as plt

# Define the derivative dy/dx
def dy_dx(x):
    return 2 * x

# Define the exact analytical solution y(x) for comparison
def y_analytical(x):
    return x**2

# Define a numerical solution for y(x) using the forward Euler method
def y_numerical(x, h):
    y = [0]  # Initialize y with the starting value, assuming y(0) = 0
    for i in range(len(x) - 1):
        y.append(y[-1] + dy_dx(x[i]) * h)  # Update y using dy/dx
    return y

# Set up the x values
plot_x = np.linspace(0, 10, 100)
x = np.linspace(0, 10, 10)
h = x[1] - x[0]  # Step size

# Compute the difference between analytical and numerical solutions
difference = y_analytical(x) - np.array(y_numerical(x, h))

# Set up the figure with two subplots
fig, axs = plt.subplots(2,1, figsize=(10,8))

# Left plot: Analytical and numerical solutions
axs[0].plot(plot_x, y_analytical(plot_x), label='Analytical', linestyle='dashed', linewidth=2)
axs[0].scatter(x, y_numerical(x, h), label='Numerical', linestyle='solid', color='red')
axs[0].set_title('Analytical vs Numerical')
axs[0].set_xlabel('x')
axs[0].set_ylabel('y')
axs[0].legend()

# Right plot: Difference between solutions
axs[1].scatter(x, difference, label='Difference', color='red')
axs[1].set_title('Difference (Analytical - Numerical)')
axs[1].set_xlabel('x')
axs[1].set_ylabel('Difference')
axs[1].legend()

# Adjust layout and show the plots
plt.tight_layout()
plt.show()

Difference between the analytical and numerical solutions depends on the step size \(h\).

Html example

Initial y(0): 0.0

Step size (h): 1.0

Animation Speed

Step Calculation:

y_new = y_old + y' · h

Exact Solution

Numerical (Current)

History

Tangent (y')

Second order differential equations

Let’s consider the second order differential equation

\[ \frac{d^2y(x)}{dx^2} = -y(x) \]

This is a simple differential equation that can be solved by integration. The solution is

\[ y(x) = A \sin(x) + B \cos(x) \]

where \(A\) and \(B\) are integration constants. This is the general solution of the differential equation. The solution is not unique because the constants \(A\) and \(B\) can take any value. The solution is a sinusoidal function. The constants \(A\) and \(B\) determine the amplitude and phase of the sinusoidal function.

Numerical solution

From Taylor’s theorem, we know that the second derivative of a function \(f(x)\) can be approximated by

\[ f(x + h) = f(x) + h \frac{df(x)}{dx} + \frac{h^2}{2} \frac{d^2f(x)}{dx^2} + \ldots \]

also

\[ f(x - h) = f(x) - h \frac{df(x)}{dx} + \frac{h^2}{2} \frac{d^2f(x)}{dx^2} + \ldots \]

adding these two equations we get

\[ f(x + h) + f(x - h) = 2 f(x) + h^2 \frac{d^2f(x)}{dx^2} \]

so we can approximate the second derivative by

\[ \frac{f(x + h) + f(x - h) - 2 f(x)}{h^2} \approx \frac{d^2f(x)}{dx^2} \]

Let’s use this approximation to solve the differential equation

\[ \frac{d^2y(x)}{dx^2} = -y(x) \]

We can approximate the second derivative by

\[ \frac{y(x + h) + y(x - h) - 2 y(x)}{h^2} = -y(x) \]

This equation can be solved for \(y(x + h)\)

\[ y(x + h) = 2 y(x) - y(x - h) - h^2 y(x) \]

This equation can be used to solve the differential equation numerically. We can start from an initial value of \(y(x)\) and \(y(x - h)\) and use the equation above to calculate the value of \(y(x + h)\). This value can be used to calculate the next value of \(y(x + 2h)\) and so on. This is a simple numerical method to solve differential equations.

Let us compare the numerical solution with the analytical solution.

import numpy as np
import matplotlib.pyplot as plt

# Define the second derivative d^2y/dx^2
def d2y_dx2(x):
    return -x

# Define the exact analytical solution y(x) for comparison
def y_analytical(x):
    return -np.sin(x)

# Define a numerical solution for y(x) using the forward Euler method
def y_numerical(x, h):
    y = [0, np.sin(-h)]  # Initialize y with the starting values, assuming y(0) = 0 and y(-h) = sin(-h)
    for i in range(1, len(x) - 1):
        y.append(2 * y[-1] - y[-2] - h**2 * y[-1])  # Update y using d^2y/dx^2
    return y

# Set up the x values
plot_x = np.linspace(0, 10, 100)
x = np.linspace(0, 10, 20)
h = x[1] - x[0]  # Step size

# Compute the difference between analytical and numerical solutions
difference = y_analytical(x) - np.array(y_numerical(x, h))

# Set up the figure with two subplots
fig, axs = plt.subplots(2,1, figsize=(10,8))

# Left plot: Analytical and numerical solutions
axs[0].plot(plot_x, y_analytical(plot_x), label='Analytical', linestyle='dashed', linewidth=2)
axs[0].scatter(x, y_numerical(x, h), label='Numerical', color='red')
axs[0].set_title('Analytical vs Numerical')
axs[0].set_xlabel('x')

axs[0].set_ylabel('y')
axs[0].legend()

# Right plot: Difference between solutions
axs[1].scatter(x, difference, label='Difference')
axs[1].set_title('Difference (Analytical - Numerical)')
axs[1].set_xlabel('x')
axs[1].set_ylabel('Difference')
axs[1].legend()

# Adjust layout and show the plots
plt.tight_layout()
plt.show()

Html example

Position y(0): 0.0

Velocity y'(0): 0.0

Step size (h): 0.5

Speed

2nd Order Step:

y_n+1 = 2y_n - y_n-1 - h²y_n

Exact (Harmonic)

Numerical

Inertia (No force)

Force (-h²y)

History

Gradient

The gradient of a scalar field is itself a vector field that points in the direction of the greatest rate of increase of that scalar field. Its magnitude indicates how rapidly the value of the scalar field changes. Formally, for a function \(f(x, y, z)\), the gradient is:

\[ \nabla f = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial f}{\partial z} \right). \]

If a function \(f\) is defined in 2D space as \(f(x, y)\), then

\[ \nabla f(x, y) = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y} \right). \]

Any scalar field \(f(x, y)\) has a corresponding gradient field \(\nabla f\). However, not every vector field is necessarily the gradient of some scalar field.

---

1D Example

For a one-dimensional function \(f(x) = \sin(x)\) on the interval \([0, 10]\), the gradient (or in this 1D case, simply the derivative) is:

\[ f'(x) = \cos(x). \]

Below is a Python example that illustrates how to compute these derivatives at a few sample points. We then represent them as small vectors placed at \(y = 2\) in a plot, pointing upward if \(f'(x)\) is positive and downward if \(f'(x)\) is negative, with a scaled magnitude.

import numpy as np
import matplotlib.pyplot as plt

# 1D function
def f(x):
    return np.sin(x)

# Its derivative (gradient in 1D)
def df(x):
    return np.cos(x)

# Sample points on [0, 10]
xs = np.linspace(0, 10, 100)
values_f = f(xs)

# Choose a few points to visualize gradient vectors
sample_points = np.linspace(0, 10, 20)
grad_values = df(sample_points)

fig, ax = plt.subplots(figsize=(8, 4))

# Plot sin(x)
ax.plot(xs, values_f, label='f(x) = sin(x)')

# Plot gradient vectors at y=2 for each sample point
for x_i, grad in zip(sample_points, grad_values):
    # We'll scale the arrow length by 0.5 for visibility
    ax.arrow(
        x_i, f(x_i), grad,0 ,
        head_width=0.1, head_length=0.1, length_includes_head=True,
        fc='green', ec='red'
    )

ax.set_ylim(-1.5, 2)
ax.set_xlabel('x')
ax.set_ylabel('f(x)')
ax.set_title('1D Gradient (Derivative) of sin(x)')
ax.legend()
plt.show()

In this plot: - The blue curve is \(\sin(x)\). - The red arrows at show the derivative \(f'(x) = \cos(x)\) at the chosen sample points. - Arrows pointing up indicate a positive derivative.

---

2D Example

Now let’s consider a scalar field in two variables. For instance:

\[ f(x, y) = \sin(x)\cos(y). \]

Let us compute partial derivatives of this function. Derivative with respect to \(x\) is:

\[ \frac{\partial f(x,y)}{\partial x} = \frac{\partial}{\partial x}[\sin(x)\cos(y)] = \cos(x)\cos(y). \]

Derivative with respect to \(y\) is:

\[ \frac{\partial f(x,y)}{\partial y} = \frac{\partial}{\partial y}[\sin(x)\cos(y)] = -\sin(x)\sin(y). \]

so the gradient of the function \(f(x, y)\) is:

\[ \nabla f(x, y) = \bigl(\cos(x)\cos(y),\; -\sin(x)\sin(y)\bigr). \]

import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D

# Define the 2D scalar field
def f2d(x, y):
    return np.sin(x) * np.cos(y)

# Create a grid for plotting
nx, ny = 60, 60
x_vals = np.linspace(0, 2*np.pi, nx)
y_vals = np.linspace(0, 2*np.pi, ny)
X, Y = np.meshgrid(x_vals, y_vals)
Z = f2d(X, Y)

# --- 3D Surface Plot ---
fig3d = plt.figure(figsize=(8, 6))
ax3d = fig3d.add_subplot(111, projection='3d')

# Create a surface plot
surf = ax3d.plot_surface(
    X, Y, Z, 
    cmap='coolwarm', 
    edgecolor='none',
    alpha=0.9
)
fig3d.colorbar(surf, ax=ax3d, shrink=0.6, label='f(x,y) = sin(x)*cos(y)')
ax3d.set_xlabel('x')
ax3d.set_ylabel('y')
# ax3d.set_zlabel('f(x,y)')
ax3d.set_title('3D Surface of f(x, y) = sin(x)*cos(y)')
plt.show()

Below is a Python example that: 1. Plots a heatmap of \(f(x, y)\). 2. Overlays gradient vectors (arrows) on a grid of points.

import numpy as np
import matplotlib.pyplot as plt

# Define the 2D scalar field
def f2d(x, y):
    return np.sin(x) * np.cos(y)

# Define partial derivatives (gradient)
def grad_f2d(x, y):
    # df/dx = cos(x)*cos(y)
    # df/dy = -sin(x)*sin(y)
    return np.cos(x)*np.cos(y), -2*np.sin(x)*np.sin(y)

# Create a grid for plotting
nx, ny = 60, 60
x_vals = np.linspace(0, 2*np.pi, nx)
y_vals = np.linspace(0, 2*np.pi, ny)
X, Y = np.meshgrid(x_vals, y_vals)
Z = f2d(X, Y)

# Compute gradient on a coarser grid for quiver plot
skip = 3
x_quiv = X[::skip, ::skip]
y_quiv = Y[::skip, ::skip]
Fx, Fy = grad_f2d(x_quiv, y_quiv)

fig, ax = plt.subplots(figsize=(8, 6))

# Heatmap of f(x,y)
c = ax.imshow(
    Z, 
    extent=[x_vals.min(), x_vals.max(), y_vals.min(), y_vals.max()],
    origin='lower',
    cmap='coolwarm'
)
fig.colorbar(c, ax=ax, label='f(x,y) = sin(x)*cos(y)')

# Quiver plot of gradient vectors
ax.quiver(
    x_quiv, y_quiv, Fx, Fy, 
    color='black', 
    pivot='mid', 
    alpha=0.8,
    width=0.003,
    scale=50
)

ax.set_xlabel('x')
ax.set_ylabel('y')
ax.set_title('Gradient of f(x, y) = sin(x)*cos(y)')
plt.show()

Interpretation:

• The heatmap shows the values of \(f(x,y)\). Red/blue corresponds to high/low values of the scalar field.
• The arrows show the local direction and magnitude of the gradient, i.e., where \(f(x, y)\) increases the most and how quickly.

This demonstrates how any scalar field (like temperature, potential, or pressure) naturally defines a vector field via its gradient. However, not every vector field arises as a gradient of a scalar field—certain mathematical conditions (like having zero curl in a simply connected domain) must be satisfied for a vector field to be the gradient of some scalar field.

Html example

Gradient Descent: Finding the Minimum

Current Calculation

Slope (f'(x)) = 0.00

x_new = 0.00 - (0.1 · Slope)

→ x_new = 0.00

Ball rolls opposite to the slope (Gradient Descent Step).

Learning Rate (Step Size) 0.20

Click anywhere on the curve to place the ball, then use controls to descend.